Question

Mark the correct alternative in each of the following: If two different dice are rolled together, the probability of getting an even number on both dice is
(a)$\frac{1}{36}$
(b)$\frac{1}{2}$
(c)$\frac{1}{6}$
(d)$\frac{1}{4}$

Answer 1

SOLUTION :

The correct option is (d) : 1/4

Given : A dice is rolled twice .

If we throw two dices then there possible outcomes are as follows:

{(1,1) (1, 2) (1, 3) (1, 4) (1, 5)(1, 6)

(2,1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)}

Total no. of possible outcomes when 2 dice are thrown = 6 x 6 = 36

Total Number of possible outcomes = 36

Let E = Event of getting even number on both dice  

Favorable outcomes(even number on both dice) : (2, 2) ,(2, 4) , (2, 6),  (4, 2) , (4, 4) ,(4, 6),  (6, 2) , (6, 4) , (6, 6)

Number of favorable outcomes = 9

Probability ,P(E) = Number of favourable outcomes / total number of outcomes

P(E1) = 9/36 = 1/4

Hence, the Probability of getting even number on both dice,  P(E1) = 1/4

HOPE THIS ANSWER WILL HELP  YOU….

Answer 2

✌️✌️Your answer ✔️✔️

$\large = >probablity = \frac{no.of \: favourable \: outcomes}{no.of \: total \: outcomes}$

=> Total outcomes = 36

=> even number on each dice = 2,4,6

=> As its 2 dices,

=> favourable outcomes (even numbers )= 9

=> 9/36

=> 1/4

=> Therefore the answer is

✔️✔️Option D✔️✔️

✔️✔️$\huge\frac{1}{4}$✔️✔️