Question

Mark the correct alternative in each of the following: The probability of getting an even number, when a die is thrown once is
(a)$\frac{1}{2}$
(b)$\frac{1}{3}$
(c)$\frac{1}{6}$
(d)$\frac{5}{6}$

Answer 1

SOLUTION :  

The correct option is (a) : 1/2

Given : A die is thrown once .

A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

Total number of outcomes are = 6

Let E = Event of getting an even number

Prime number in a die = 2, 4, 6  

Number of outcome favourable to E = 3

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 3/6  = ½  

Hence, the probability of getting an even number, P(E) = 1/2

HOPE THIS ANSWER WILL HELP  YOU…

Answer 2

✌️✌️Answer ✌️✌️

✔️✔️Option A✔️✔️

✳️ Explaination ✳️


▶️ $\large = >probablity = \frac{no.of \: favourable \: outcomes}{no.of \: total \: outcomes}$


▶️=> Even numbers = 2 , 4 , 6


▶️$= > \frac{3}{6} \\ \\ = > \frac{1}{2}$