Question

Mark the correct alternative in each of the following: The probability that a number selected at random from the numbers 1, 2, 3, ..., 15 is a multiple of 4, is
(a)$\frac{4}{15}$
(b)$\frac{2}{15}$
(c)$\frac{1}{5}$
(d)$\frac{1}{3}$

Answer 1

SOLUTION :

The correct option is (C)   : ⅕  

Given : A number is selected from 1 to 15  

Total number of possible outcome = 15

Let E = Event of getting a multiple of 4

Multiple of 4 from 1 to  25 are = 4, 8, 12

No. of outcomes  favorable to E = 3

Probability ,P(E) = Number of favourable outcomes / total number of outcomes

P(E) = 3/15 = 1/5

Hence, the Probability of getting a multiple of 4  from 1 to  15,P(E)  is 1/5.

HOPE THIS ANSWER WILL HELP  YOU….

Answer 2

✔️✔️ Option C✔️✔️

✳️ Explaination ✳️

$\large = >probablity = \frac{no.of \: favourable \: outcomes}{no.of \: total \: outcomes}$


=> Multiples of 4 from 1 to 15


=> 4,8,12


=> 3/15


=> 1/5


=> Therefore the answer is


✔️✔️ Option C✔️✔️



✔️✔️1/5 ✔️✔️