Question

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Frame the equations and solve:

Raju is four years younger than Biju. Sum of their ages is 28.Find their ages.

Answer 1

Define x:

Let Biju be x years old.

Raju = x - 4 years old

Form equation:

Sum of their age is 28

⇒ x + (x - 4) = 28

Solve x:

x + (x - 4) = 28

x + x - 4 = 28

2x - 4 = 28

2x = 32

x = 16

Find their age:

Biju = x = 16

Raju = x - 4 = 16 - 4 = 12

Answer: Biju is 16 years old and Raju is 12 years old.

Answer 2

Let the age of biju be 'x' years.

Given that Raju is four years younger than Biju.

So, the age of Raju will be x - 4.

Now,

Given that Sum of their ages is 28:

= > x + x - 4 = 28

= > 2x - 4 = 28

= > 2x = 32

= > x =16.

Therefore:

The age of Biju is 16 years.

The age of Raju is 16 - 4 = 12 years.

Hope this helps!