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The sum of first 6 terms of an ap is 57 and the sum of first 10 terms 155 find the algebraic form of this AP
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Answer:
Given a=2,l=9 and S=155
S=
2
n
(a+l)
155=
2
n
(2+29)
⇒n=10
l=a+(n−1)d
29=2+(10−1)d
⇒d=3
So the common difference is 3
Step-by-step explanation:
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