Question

Marked price of two articles A and B is in the ratio of 3:4. Shopkeeper sold article A and article B at the discount of x % and (x+8)% respectively. Shopkeeper made a profit of 20% on selling article B and found that its cost price is equal to selling price of article A. Find the marked of article B when article A is sold for Rs 972 at two successive discounts of x/2% and 2x%?​

Answer 1

Answer:

2400 IND.

Step-by-step explanation:

let m.p of A & B be 3y and 4y

assume C.p of B = 100% so s.p = 120%

4y×[100-(x+8)]% ×100/120=3y(100-x)%

20/6 *(92 - x) = 3 (100 - x)

1840 - 20x = 1800 - 18x

2x = 40 => x = 20

now discounts x/2% = 20/2 = 10% & 2x

= 2(20) = 40%

s.p of A = 972

3y *(100-10)% (100-40)% = 9720

3y*90% *60% = 972

162y = 97200 => y = 600

M.P of article B=4y = 4(600)=2400