Math, asked by asaklunova, 10 months ago

Marking brainliest for correct answer :

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Answered by sam3535
0

Answer:

a.

probability of opening lock in one attempt=1/10

b.

i)Number of possible combinations

0-0,1,2,3-----9 =10

1-0,1,2--------9 =10

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9-0,1,2,------9 =10

Number of possible combinations=10×10=100

ii)probability of opening lock in one attempt=1/100

c.

i)Number of possible combinations

0-1-0,1,2------9

-2-0,1,2-----9

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-9-0,1,2,3----9 = 100

Similarly for 10 numbers= 100×10 =1000

Number of possible combinations=1000

ii)probability of opening lock in one attempt=1/1000.

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