Marking brainliest for correct answer :
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Answer:
a.
probability of opening lock in one attempt=1/10
b.
i)Number of possible combinations
0-0,1,2,3-----9 =10
1-0,1,2--------9 =10
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9-0,1,2,------9 =10
Number of possible combinations=10×10=100
ii)probability of opening lock in one attempt=1/100
c.
i)Number of possible combinations
0-1-0,1,2------9
-2-0,1,2-----9
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-9-0,1,2,3----9 = 100
Similarly for 10 numbers= 100×10 =1000
Number of possible combinations=1000
ii)probability of opening lock in one attempt=1/1000.
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