Question

Marks: 3/70
In the meter bridge experimental set
up, shown in the figure, the null point
'D' is obtained at a distance of 40 cm
from end A of the meter bridge wire. If
a resistance of 10 12 is connected in
series with Ri, null point is obtained
at AD = 60 cm. Calculate the values
of R1 and R2.​

Answer 1

Answer:

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Answer 2

$\frac{R_{1} }{R_{2} } = \frac{40}{60} = \frac{2}{3}$

$\frac{R_{1}+ 10 }{R_{2} } = \frac{60}{40} = \frac{3}{2}$

$\frac{R_{1} }{R_{2} } + \frac{10}{R_{2} } = \frac{3}{2}$

$\frac{2}{3} + \frac{10}{R_{2} } = \frac{3}{2}$

$R_{2} = 12$Ω

substituting for R2 and finding the value of R1

$R_{1} = 8$Ω