Question

marks each
in quadrilateral ABCD. ZA:CB:20:2D = 2:3:4:6. Find all the angles of ABCD​

Answer 1

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$let</strong><strong>$

$angle \: of \: equdrilateral \: abcd \: are$

$2x \: 3x \: 4x \: 6x$

$we \: know$

$sum \: of \: angle \: ofequadrilateral = 360$

$therefore$

$< a + < b + < c + < d = 360$

$2 x\: 3 x\: 4 x\: 6x = 360$

$15x = 360$

$therefore \: x = 24$

Answer 2

Answer:

Let the common ratio between the angles be = x

Step-by-step explanation:

angles of quadrilateral ABCD are:-

2x,3x,4x,6x

we know,

sum of angles of quadrilateral = 360°

2x+3x+4x+6x=360°

15x=360°

x=360/15

x=24°

A=2x

A=2×24

=48°

B=3x

=3×24

=72°

C=4x

=4×24

=96°

D=6x

=6×24

=144°