. Marks obtained by 40 students in a short assessment is given below, where a and b are
two missing data.
Marks ============ 5 6 7 8 9
Number of Students= 6 A 16 13 b
If the mean of the distribution is 7.2, find a and b.
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Sigma fi Xi fixi
6 5 6(5)=30
a 6 =6a
16 7 16(7)=112
13 8 13(8) =104
b 9 =9b
Summation of fixi=30+6a+112+104+9b=246+6a+9b
Summation of fi=6+a+16+13+b=40
=35+a+b=40
a+b=5.............(1)
Mean=sigmafixi/fi
7.2=246+6a+9b/40
288= 246+6a+9b
42=6a+9b............(2)
From (1) b=5-a sub in(2)
Then., 42=6a+9(5-a)
42=6a+45-9a
-3=-3a
a=-3/-3=1
Therefore, a=1............(3)
Sub (3) in (1)
a+b=5
1+b=5
b=5-1=4
Therefore., a=1 and b=4
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