Marks obtained by 50 students in Statistics, presented along with frequencies in a tabular form, is an example of
Answers
Answer:
Sets in mathematics book
Answer:
0−10 10−20 20−30 30−40 40−50 50−60 60−70 70−80
Frequency 2 5
8
16
9
5
3
2
Cumulative Frequency 2
7
15
31
40
45
48
50
Total number of students=n=50
2
n
=
2
50
=25,
As 25<31,
So 30−40 is the median class.
l is the lower limit of median class, so l=30
h is the size of class interval, so h=40−30=10
f is the frequency of median class, so f=16
F is the cumulative frequency of class preceding the median class, so F=15
Median=l+(
f
2
n
−F
)×h
Median=30+(
16
2
50
−15
)×10
Median=30+(
16
10
)×10
Median=30+(
16
100
)
Median=36.25
Hence, the median is=36.25
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SIMILAR QUESTIONS
star-struck
What is the median salary of an employee? If the frequency table represents the number of employees and their salaries.
Salary
1000
500
1500
2000
3500
Frequency
2
1
5
7
2
Medium
View solution
>
Find the median of the following data.
x 10 20 30 40 50
f 2 3 2 3 1