Question

marks scored by the students of class 12th in mathematics are given in the form of a frequency distribution
0-10|10-20|20-30|30-40|40-50
5 12 16 12 5 ​

Answer 1

Answer:

C.I f cf 0 - 10 2 2 10 - 20 10 12 20 - 30  12 24 30 - 40  15 39 40- 50  13 52 50 - 60 8 60 60 - 70 4 64

To find median, we need to find Median class first,

Total no of students(N)=64

2N=26/2=32

From Cf we can see 32 is more than 24 and less than 39, So, Median Class =30−40

Now,

M=l+f(2/N−C)×h

where, l= lower limit of median class=30,

C= preceding cumulative frequency of median class=24,

f= frequency of median class=15,

h= class size=10

M=30+15/32−24×10

=30+158×10

=30+5.33=35.33

Answer 2

Answer:

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