Question

marry is twice older than her sister in 5years time , she will be 2years older than her sister
find how old are they both now​

Answer 1

Answer:

Let age of Mary = m

Let age of her sister = s

Given that, m=2s

After five years, Mary will be 2 years older than her sister.

(m + 5) = (s + 5) + 2

Therefore m = S + 2

m = 2s => s + 2 = 2s => s = 2

Therefore m = 4

Mary is 4 years old and her sister is 2 years old.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let age of mary =m

Let age of her sister =s

Given that, m=2s

After 5 years, mary will be 2 years older than her sister.

(m+5)=(s+5)+2

∴m=s+2

m=2s⇒s+2=2s⇒s=2

∴m=4

Mary is 4 years old and her sister is 2 years old.

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