marry istwice older then her sister.in 5yearstime,she will be 2 years older than her sister,find how old are they both now.
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H€YA!!
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Let the Age of Mary's Sister be X years .
Then the age of Mary = 2X years .
After 5 years
( X +5 ). +2 = (2X +5)
X+ 7 = 2X +5
-X = -2
X =2
▶Age of sister = 2 years
▶Age of Mary = 4 years
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Let the Age of Mary's Sister be X years .
Then the age of Mary = 2X years .
After 5 years
( X +5 ). +2 = (2X +5)
X+ 7 = 2X +5
-X = -2
X =2
▶Age of sister = 2 years
▶Age of Mary = 4 years
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