Question

Mars has about 1/10 the mass of Earth and about 1/2 the diameter of Earth. The acceleration (in m/s2) of a body falling near the surface of Mars is about: (Take g = 9.8 m/s2)

Answer 1

The acceleration due to gravity at mars is 3.92 m/s²

•As we all know , g is acceleration due to gravity

& value of g at near earth surface is 9.8m/s²

•Also, g = (GM)/R²

•where

G = universal Gravitational const.

M = Mass of body which attracts object

R = Radius of Body

•In Earth

let say mass of earth is M & radius is R

so, g(Earth)= (GM)/R² ____(1)

•According to question

In Mars

mass of mars = M/10

radius of mars = R/2

so, g = [G(M/10)]/(R/2)²

g(mars) = 4GM/10(R)²

g(mars) = 4g(Earth)/10

g(mars) = 4×9.8/10

g(mars) = 3.92 m/s²

•The acceleration due to gravity at mars is 3.92 m/s²