Question

Mart
CARTEA
it
Annual Assessment
Sub-Caglish
and we the questions given below
Rende​

Answer 1

Answer:

|x| (6x2 + 1) = 5x2

We know that |x2| = x2

Let y = |x|

So, y2 = x2

So, y (6y2 + 1) = 5y2

6y2 + 1 = 5y

6y2 -5 + 1 = 0

y = or

Since, y = |x|

y = or , or

Since we have cancelled y in our first step, x = 0 is also a solution

So, Number of possible solutions = 4 + 1 = 5