Question

Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result? StartFraction S Over 2 pi r EndFraction equals h. – r = h StartFraction S minus r Over 2 pi r EndFraction equals h. = h S – S minus StartFraction r Over 2 pi EndFraction equals h. = h S – S minus StartFraction 2 pi Over r EndFraction equals h. = h

Answer 1

Answer:

h = (S - 2πr²) / 2πr

Step-by-step explanation:

Since we are given that

S = 2πrh + 2πr²

Subtracting by 2πr² on both sides we get

S - 2πr² = 2πrh

Dividing by 2πr on both sides we get

(S - 2πr²) / 2πr = h

So

The final equation is

h = (S - 2πr²) / 2πr

I hope it helpful compare it with your given options and deduce the right answer by yourself.

Answer 2

Answer:

A) StartFraction S Over 2 pi r EndFraction equals h. – r = h

Step-by-step explanation:

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