Question

Martin is four times the as old as his brother Luther at present . After 10 years he will be twice age of his brother. Find their present age.​

Answer 1

Let Luther's age be x and Martin's age be 4x. This is their respective ages currently.

Then,

According to the problem, after 10 years the age of Luther will be (x + 10) and the age of Martin will be 4x + 10. All we did here was express what was stated in the problem using x for Luther and 4x for Martin and adding 10,

Therefore,

4 x + 10 = 2 (x + 10)

Because after 10 years Martin "will be twice the age of his brother."

Now solve the above equation for x,

4x + 10 = 2 (x + 10)

4 x + 10 = 2 x + 20

4x - 2x = 20 - 10

2x = 10

x = 5

Remember, we said Luther would be represented by x, right? Therefore, Luther is 5. Martin, is represented by 4x,

Therefore, Martin is 4(5) or 20

Luther is 5

Martin is 20

Now, let's check our work,

We must meet two conditions according to our problem:

First, Martin must be four times as old as his brother currently or at present. 5 * 4 is in fact, 20.

Second, after 10 years Martin needs to be twice the age of Luther,

In 10 years Luther will be 15, and Martin will be 30.

Answer 2

Answer:

at present, age of martin is four times

let age of luther be x and age of martin be y

hence, x=4y

after 10 years, age of luther is x+10 and age of martin is y+10

now, x+10=2(y+10)

by solving the equation we get y=10

and x=40

therefore age of martin is 40 years and age of luther is 10 years