Math, asked by viva8017614369, 10 months ago

Mary and david can do a work individually in 10 days and 15 day respectively. At first Mary alone worked for 4 day then David alone worked for 5 days and left . Maria came and completed the remaining work in 4 days . if mary David and Maria would work together let's calculate in how many days they would complete the work .

Answers

Answered by Anonymous
1

Mary and david can do a work individually in 10 days and 15 day respectively. At first Mary alone worked for 4 day then David alone worked for 5 days and left .

Maria came and completed the remaining work in 4 days .

if mary David and Maria would work together.

Then according to the question :-

10+15+5+4+4= 28.

Hence in 28 days they would complete the work .

Answered by Anonymous
0

Step-by-step explanation:

Mary and david can do a work individually in 10 days and 15 day respectively. At first Mary alone worked for 4 day then David alone worked for 5 days and left .

Mary and david can do a work individually in 10 days and 15 day respectively. At first Mary alone worked for 4 day then David alone worked for 5 days and left .Maria came and completed the remaining work in 4 days .

Mary and david can do a work individually in 10 days and 15 day respectively. At first Mary alone worked for 4 day then David alone worked for 5 days and left .Maria came and completed the remaining work in 4 days .if mary David and Maria would work together.

Mary and david can do a work individually in 10 days and 15 day respectively. At first Mary alone worked for 4 day then David alone worked for 5 days and left .Maria came and completed the remaining work in 4 days .if mary David and Maria would work together.Then according to the question :-

Mary and david can do a work individually in 10 days and 15 day respectively. At first Mary alone worked for 4 day then David alone worked for 5 days and left .Maria came and completed the remaining work in 4 days .if mary David and Maria would work together.Then according to the question :-10+15+5+4+4= 28.

Mary and david can do a work individually in 10 days and 15 day respectively. At first Mary alone worked for 4 day then David alone worked for 5 days and left .Maria came and completed the remaining work in 4 days .if mary David and Maria would work together.Then according to the question :-10+15+5+4+4= 28.Hence in 28 days they would complete the work .

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