Mary bought two tables for Rs. 3605. She sold one at a profit of 15% and the other at a loss of 9%. If Mary obtained the same amount for each fan, find the cost price of each fan.
Answers
Answered by
291
Let cost of table fans be Rs. x and Rs. y respectively
As per question,
=> x+y = 3605
=> y = 3605-x ...(1)
SP of,
=> First fan = x + 15% of x = Rs. 115x/100
=> Second fan = y - 9% of y = Rs. 91y/100
As per question,
=> 115x/100 = 91y/100
=> 115x = 91y
=> 115x = 91(3605-x) (From 1)
=> 115x = 328055-91x
=> 115x+91x = 328055
=> 206x = 328055
=> x = 328055/206 = Rs. 1592.50
∴ y = (3605-1592.50) = Rs. 2012.50
As per question,
=> x+y = 3605
=> y = 3605-x ...(1)
SP of,
=> First fan = x + 15% of x = Rs. 115x/100
=> Second fan = y - 9% of y = Rs. 91y/100
As per question,
=> 115x/100 = 91y/100
=> 115x = 91y
=> 115x = 91(3605-x) (From 1)
=> 115x = 328055-91x
=> 115x+91x = 328055
=> 206x = 328055
=> x = 328055/206 = Rs. 1592.50
∴ y = (3605-1592.50) = Rs. 2012.50
Answered by
66
Answer:
Step-by-step explanation:first fan cost be x and other fan cost is 3605-x
So
ATQ,
SP of first fan=SP of second fan
100+profit%/100×cp=100-loss%/100×cp
115x/100=91/100×(3605-x)
115x=91(3605-x) ::dividing both by 100
115x=328055-91x
115x+91x=328055
206x=328055
x=328055/206=1592.5
Other fan cost=3605-1592.5=2012.5
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