Mary chooses a number and does the following. First, she multiplies it by 2, and then she adds 16. The result is again multiplied by 2 and 16 is added, and so on by the same pattern. Which (natural one digit) number did she choose if the result was 68 at some time?
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Answer:
Step-by-step explanation:
Let the number she chooses is x
Step1 :
By first condition :
2x+16 ------- Eq (1)
By 2nd condition.
2(2x+16) +16
4x +32 +16
4x +48 ---------Eq (2)
By given condition at some point the sum of pattern should by 68 .
So using Eq(2)
4x +48=68
4x=68-48
x=20/4
x=5
So the natural one digit number will be 5 .
Hope it answer yours Qs.
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