Math, asked by albia60, 3 months ago

Mary has a total of rs 300 in coins of denominations rs 1 rs 2 and rs 5. the number of rs 2 coins is 3 times the number of rs 5 coins. the total number of coin is rs 160 . How many coins of each denomination are with her​

Answers

Answered by iTzRiYaNsH
5

Answer:

Given, Total number of coins =160

Given that the number of Rs.2 coins are 3 times the number of Rs. 5 coins.

Number of Rs. 5 coins =x

Number of Rs. 2 coins =3x

Number of Re. 1 coins =160−(x+3x)=160−4x

Total value of coins = Rs. 300

So, 5×x+2×3x+1×(160−4x)=300

5x+6x+160−4x=300

7x=140

x=20

So, number of Rs. 5 coins =20

Number of Rs. 2 coins =60

Number of Re. 1 coins =80

Answered by Anonymous
9

Answer:

Answer:

Given, Total number of coins =160

Given that the number of Rs.2 coins are 3 times the number of Rs. 5 coins.

Number of Rs. 5 coins =x

Number of Rs. 2 coins =3x

Number of Re. 1 coins =160−(x+3x)=160−4x

Total value of coins = Rs. 300

So, 5×x+2×3x+1×(160−4x)=300

5x+6x+160−4x=300

7x=140

x=20

So, number of Rs. 5 coins =20

Number of Rs. 2 coins =60

Number of Re. 1 coins =80

hope it helps you

Similar questions