Mary has a total of rs 300 in coins of denominations rs 1 rs 2 and rs 5. the number of rs 2 coins is 3 times the number of rs 5 coins. the total number of coin is rs 160 . How many coins of each denomination are with her
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Answered by
5
Answer:
Given, Total number of coins =160
Given that the number of Rs.2 coins are 3 times the number of Rs. 5 coins.
Number of Rs. 5 coins =x
Number of Rs. 2 coins =3x
Number of Re. 1 coins =160−(x+3x)=160−4x
Total value of coins = Rs. 300
So, 5×x+2×3x+1×(160−4x)=300
5x+6x+160−4x=300
7x=140
x=20
So, number of Rs. 5 coins =20
Number of Rs. 2 coins =60
Number of Re. 1 coins =80
Answered by
9
Answer:
Answer:
Given, Total number of coins =160
Given that the number of Rs.2 coins are 3 times the number of Rs. 5 coins.
Number of Rs. 5 coins =x
Number of Rs. 2 coins =3x
Number of Re. 1 coins =160−(x+3x)=160−4x
Total value of coins = Rs. 300
So, 5×x+2×3x+1×(160−4x)=300
5x+6x+160−4x=300
7x=140
x=20
So, number of Rs. 5 coins =20
Number of Rs. 2 coins =60
Number of Re. 1 coins =80
hope it helps you
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