Mary is 3times older than Nandhini after 10years the sum of their ages will be 80.find their present ages
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let
nandhini's age=x
mary's age=3x
After ten years sum of their ages will be 80
According to problem
10+x+10+3x=80
20+4x=80
4x=80-20
4x=60
x=60/4
x=15
nandhini's age=x=15
mary's age=3x=3*15
=45
nandhini's age=x
mary's age=3x
After ten years sum of their ages will be 80
According to problem
10+x+10+3x=80
20+4x=80
4x=80-20
4x=60
x=60/4
x=15
nandhini's age=x=15
mary's age=3x=3*15
=45
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