Mary is three times older than nandhini.after 10 years the sum of their ages will be 80. find their present ages
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Let Mary's age be x
and Nandhini's be y
so, 3x=y [Call this as 1st equation]
after 10 years
Mary=x+10
Nandhini=y+10
Sum of their ages
x+10 + y + 10=80
x=15[after substituting 1st equation and solving]
3x=y[1st equation]
3 x 15 = y
45 = y
Mary age = 15
Nandhini age = 45
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