Math, asked by k7ira1bakishpurnandw, 1 year ago

mary is three times older than nandhini after 10 years the sum of their ages will be 80 find their present ages

Answers

Answered by khanujarashmit
41
Let nadini age be = x years . Then Mary age will be = 3x years After 10 years according to Q's: X+10+3x+10 = 80 => 4x= 80-20 => x= 60=15 So present age of nandini = 15 years and Mary age will be 3x = 3*15= 45 years
Answered by wifilethbridge
3

Answer:

The present age of Nandini is 15 years and present age of Mary is 45 years.

Step-by-step explanation:

Let the present age of Nandini be x

Since we are given that the present age of Mary is three times the age of Nandini

So, present age of Mary = 3x

After 10 years Mary's age = 3x+10

After 10 years Nandini's age = x+10

We are given that after 10 years the sum of their ages will be 80

So, 3x+10+x+10=80

4x+20=80

4x=60

x=15

Thus the present age of Nandini is 15 years

Present age of Mary = 3x = 3 \times 15 = 45 years

Hence the present age of Nandini is 15 years and present age of Mary is 45 years.

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