Mary is twice older than her sister. in 5 years of time, she will be 2years older than her sister. find how old are they both now.
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Mary's age is 4 years, while her sister's age is 2 years...
This can be attained by the sum as shown below:-
Sister's age be x years. Mary's age is 2x years.
After 5 years, their age:-
Sister's age=x+5 years
Mary's age=2x+5
A.T.P.:-
x+5+2=2x+5
=>x+7=2x+5
=>x-2x=5-7
=>-x=-2
=>x=2
Therefore, Mary's age=(2*2) years=4 years
sister's age = 2 years...
This can be attained by the sum as shown below:-
Sister's age be x years. Mary's age is 2x years.
After 5 years, their age:-
Sister's age=x+5 years
Mary's age=2x+5
A.T.P.:-
x+5+2=2x+5
=>x+7=2x+5
=>x-2x=5-7
=>-x=-2
=>x=2
Therefore, Mary's age=(2*2) years=4 years
sister's age = 2 years...
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