Question

Mary is twice older than her sister. In 5 years time , she will be two years older than her sister . Find how old are they both now.

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Answer 1

Answer:

Step-by-step explanation:

Let present age of Mary's sister = x

So let Present age of Mary = 2x

After 5 years ,

                      Mary's Sisters age = x+5

                       Mary's age = 2x+5

Mary's age = Mary's Sisters age + two years

                          2x+5 = (x+5 ) + 2

                          2x+5 = x+5+2  

                             2x = x+7 -5

                          2x-x = 7-5

                                 x=2    

So, Mary's Sister is 2 years old.

and Mary is (2x =2 *2  = 4 )4 years Old

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Answer 2

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Let the present age of Mary sister = x

therefore, the present age of Mary = 2x

After 5 years,

Mary Sisters age = x + 5

Mary age = 2x + 5

According to Question,

Mary age = Mary Sisters age + two years

=> 2x + 5 = (x + 5 ) + 2

=> 2x + 5 = x + 5 + 2

=> 2x = x + 7 - 5

=> 2x - x = 7 - 5

=> x = 2

Hence, Mary Sister is 2 years old.

and Mary age = 2x = 2×2 = 4 years.