Question

Mary is twice older than her sister. In 5 years time, she will be 2 years older than her
sister. Find how old are they both now, ​

Answer 1

Answer:

Mary's age will be 4 and her sister's age will be 2

Step-by-step explanation:

Let Mary's age be x

So her sister's age=x÷2

After 5 years

Mary's age=x+5

Her sister's age=x÷2+5

So if we take Mary's sister's age be 2 then Mary's age will be 4

After 5 years Mary's age= 4+5=9 years

Her sister's age=2+5=7

So she is 2 years older than her sister

Answer 2

Answer:

$lets \: the \: age \: of \: marys \: sister \: = \: x \: says \: \\ marys \: age \: = 2 \times x = 2x \\ after \: 5 \: years \: her \: sisters \: age \: \\ = (x + 5)years \\ = (2x + 5)years \\ after \: 5 \: years \: marys \: age \: \\ according \: to \: the \: sum \\ 2x + 5 = (x + 5) \: + 2 \\ 2x - x = 5 + 2 - 5 \: \: \: \: \: x = 2 \\ there \: fore \: the \:age \: of \: mary \: s \: sister \: = x = 2 \: years \\ marys \: age = 2x = 2 \times 2 = 4 \: yesrs$