Math, asked by vishwaneraj1, 1 year ago

Mary is twice older than her sister. In 5 years time, she will be 2 years older than her sister. Find how old are they both ?

Answers

Answered by Tishajain
26
let mary sister present age=x
mary's age=2x
age of sister after 5 years=x+5
age of mary after 5 years=2x+5
according to problem
mary age after 5 years=(sisters ageafter 5 years)+2
2x+5=x+5+2
2x+5=x+7
2x-x=7-5
1x=2
x=2/1
x=2 
Answered by vasisharath029
4

Answer:

2

Step-by-step explanation:

let Mary sister present age=x

Mary's age=2x

age of sister after 5 yrs =x+5

age of Mary ". ". =2x +5

Mary age after 5 yrs(sisters age after 5 yrs)+3

2x+5=x+5+2

2x+5=x+7

2x-x=7-5

1x=2x=2

Hope it helps you

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