Mary is twice older than her sister. In 5 years time, she will be 2 years older than her sister. Find how old are they both ?
Answers
Answered by
26
let mary sister present age=x
mary's age=2x
age of sister after 5 years=x+5
age of mary after 5 years=2x+5
according to problem
mary age after 5 years=(sisters ageafter 5 years)+2
2x+5=x+5+2
2x+5=x+7
2x-x=7-5
1x=2
x=2/1
x=2
mary's age=2x
age of sister after 5 years=x+5
age of mary after 5 years=2x+5
according to problem
mary age after 5 years=(sisters ageafter 5 years)+2
2x+5=x+5+2
2x+5=x+7
2x-x=7-5
1x=2
x=2/1
x=2
Answered by
4
Answer:
2
Step-by-step explanation:
let Mary sister present age=x
Mary's age=2x
age of sister after 5 yrs =x+5
age of Mary ". ". =2x +5
Mary age after 5 yrs(sisters age after 5 yrs)+3
2x+5=x+5+2
2x+5=x+7
2x-x=7-5
1x=2x=2
Hope it helps you
Similar questions