Question

Mary is twice older than her sister in 5 years time she will be 2 years older than her sister find how old are they both now​

Answer 1

Hello everyone!

Solution:- Let the present age of Mary sister be x.

Therefore, age of Mary is 2x.

Now , in five years time:

Mary's age would be x+5 years.

Her sister age will be (2x+5)

Atq,

Marry will be 2 years old than her after 5 years.

So, 2x +5= x+5+2

2x+5 = x +7

x = 2

Marry sister age is 2 years.

Her sister's age is 7 years.

Answer 2

Answer:

Marry's age is 4

and marry's sister age is 2