Mary is twice older than her sister.In 5years time, she will be 2years older than her sister. Find how old are they both now.
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Mary is twice older than her sister. In 5 years time, she will be 2 years older than her sister find how old are they both now.
solution :
Let present age of Mary's sister = x
therefore Present age of Mary = y = 2x
After 5 years ,
Mary's Sisters age = x+5
Mary's age = 2x+5
According to Question ,
Mary's age = Mary's Sisters age + two years
2x+5 = (x+5 ) + 2
2x+5 = x+5+2
2x = x+7 -5
2x-x = 7-5
x=2
hence Mary's Sister is 2 years old.
and Mary is (2x =2 *2 = 4 )4 years Old !!
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