Question

Mary is twice older than her sister .ln 5 years time, she will be 2years older than her sister. Find how old are they both now ?​

Answer 1

Answer:

Mary is twice older than her sister. In 5 years time, she will be 2 years older than her sister find how old are they both now.

solution :

       Let present age of Mary's sister = x

           therefore Present age of Mary = y = 2x

   After 5 years ,

                 Mary's Sisters age = x+5

                 Mary's age = 2x+5

According to Question ,

                 Mary's age = Mary's Sisters age + two years

                   2x+5 = (x+5 ) + 2

                     2x+5 = x+5+2

                     2x = x+7 -5

                   2x-x = 7-5

                     x=2

hence Mary's Sister is 2 years old.

and Mary is (2x =2 *2  = 4 )4 years Old !!

Hope This helps You!!

Answer 2

The present age of Mary and her sister :-

• The present age of Mary = 4 years.
• The present age of Mary's sister = 2 years.

Given :

• Mary is twice older than her sister.
• After 5 years, she will be 2 years older than her sister.

To Find :

• The present age of Mary and her sister.

Solution :

Let,

The present age of Mary's sister be x.

The present age of Mary be 2x because according to the question, Mary is twice older than her sister.

First, we need to find the value of x.

After 5 years,

The age of Mary's sister = x + 5.

The age of Mary = 2x + 5.

According to the condition,

After 5 years, she will be 2 years older than her sister.

Age of Mary = Age of Mary's sister + 2 years.

$\bf \implies (2x + 5) = (x + 5) + 2 \\ \\ \\ \bf \implies 2x + 5 = x + 5 + 2 \\ \\ \\ \bf \implies 2x + 5 = x + 7 \\ \\ \\ \bf \implies 2x - x = 7 - 5 \\ \\ \\ \bf \implies 1x = 2 \\ \\ \\ \: \: \bf \therefore \: \: x = 2$

So, the present age of Mary and her sister :-

★ The present age of Mary's sister = x = 2 years.

★ The present age of Mary = 2x = 2 × 2 = 4 years.

Hence,

The present age of Mary is 4 years and the present age of her sister is 2 years.