Math, asked by Motianimaanit, 2 months ago


Mary painted 3/8 of the table, Jane painted 2/8 of the table. How much of the
table did the girls paint

Answers

Answered by sarveshaingale08
3

Answer:

mary \: painted \:  \frac{3}{8} of \: the \: table \\ jane \: painted \:  \frac{2}{8} of \: the \: table \\ girls \: painted \: the \: table \: in \: total \\  =  \frac{3}{8}  +  \frac{2}{8}  \\  =  \frac{3 + 2}{8}  \\  =  \frac{5}{8}  \\  \\ therefore \: girls \: painted \:  \frac{5}{8} of \: the \: table

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Answered by anvishamore
1

Step-by-step explanation:

Mary and jene were girls

Mary painted = 3/8

Jane painted =2/8

 \frac{3}{8} x +  \frac{2}{8}

 =  \frac{3 + 2}{8x}

 \frac{5}{8}

Hope this helps you

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