Mary’s age is two third that of Peter’s. Two years ago Mary’s age was half of what
Peter’s age will be in 5 years’ time. How old is Peter now?
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Answered by
4
Mary's age is 2/3 that of Peter's. Two years ago Mary's age was 1/2 of what Peter's age will be in 5 years' time. how old is Peter now?
**
let x=Peter's age now
2x/3=Mary's age now
two years ago, Mary's age=(2x/3)-2=(2x-6)/3
5 years from now, Peter's age=(x+5)
((2x-6)/3)/(x+5)=1/2
(2x-6)/3(x+5)=1/2
4x-12=3x+15
x=27
ans:
Peter's age now=27
hope it helps ☺
**
let x=Peter's age now
2x/3=Mary's age now
two years ago, Mary's age=(2x/3)-2=(2x-6)/3
5 years from now, Peter's age=(x+5)
((2x-6)/3)/(x+5)=1/2
(2x-6)/3(x+5)=1/2
4x-12=3x+15
x=27
ans:
Peter's age now=27
hope it helps ☺
shahzaibali77owtqat:
i I didn't understand the calculation
Answered by
2
Let Peter's age be x.
Then Mary's age = 2x/3
Two years ago Mary's age = (2x/3)-2
Peter's age after 5 years = 5+x
therefore,
(2x-6)/3 = (5+x)/2
3(x+5) = 2(2x-6)
3x+15 = 4x-12
x=27
Peter's age now=27
Happy to help ☺
Then Mary's age = 2x/3
Two years ago Mary's age = (2x/3)-2
Peter's age after 5 years = 5+x
therefore,
(2x-6)/3 = (5+x)/2
3(x+5) = 2(2x-6)
3x+15 = 4x-12
x=27
Peter's age now=27
Happy to help ☺
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