Question

Mary's father harvested 2 150 mangoes on Monday and 2 350 on Tuesday. He divided the mangoes among his 10 children. How many mangoes did each child get? ​

Answer 1

SOLUTION

GIVEN

• Mary's father harvested 2150 mangoes on Monday and 2350 on Tuesday.

• He divided the mangoes among his 10 children.

TO DETERMINE

The number of mangoes each child got

EVALUATION

Here it is given that Mary's father harvested 2150 mangoes on Monday and 2350 on Tuesday.

Total number of mangoes

= 2150 + 2350

= 4500

Now it is given that he divided the mangoes among his 10 children

So the required number of mangoes each child got

$= 4500 \div 10$

$= 450$

FINAL ANSWER

The number of mangoes each Child got = 450

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Answer 2

Given :- Mary's father harvested 2150 mangoes on Monday and 2350 on Tuesday. He divided the mangoes among his 10 children. How many mangoes did each child get ?

Solution :-

from given data we have,

→ Mary's father harvested mangoes on Monday = 2150 mangoes

→ Mary's father harvested mangoes on Tuesday = 2350 mangoes

then,

→ Total mangoes Mary's father harvested in both days = 2150 + 2350 = 4500 mangoes.

also, given that,

→ Mary's father divided the mangoes amount his = 10 children.

therefore,

→ Mangoes each child gets = (Total mangoes Mary's father harvested)/(Total children) = (4500/10) = 450 mangoes . (Ans.)

Hence, Each child gets 450 mangoes.

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