Question

mas
A bomb burst in three fragments in which two fragments of equal mass of 1 kg each moving with
speed v right angle to each other while third fragment of having mass twice that of either masses. If
kinetic energy of system (all masses) increase by 96 J after bursting then find out CORRECT
statement about third fragment :-
(A) Will move with speed 4 m/s at angle of 135° to either.
(B) Will move with speed 4/2 m/s at angle of 135º to either.
(C) Will move with speed 412 m/s at angle of 45° to either.
(D) Will move with speed 4 m/s at angle of 45° to either.​

Answer 1

Answer:

The underlying force is 0  

Beginning energy = last force  

Last force:  

Resultant force for the two is.  

Mass is consistent and depends not on the heading.  

12² + 9² = 225  

The resultant speed = √225 = 15m/s  

Since the mass is equivalent we have.  

Force = 15m  

Give the speed of the third one a chance to be v  

The last force is = mv + 15m  

0 = mv + 15m  

- 15m = mv  

v = - 15  

The speed of the third one is :  

15 m/s