Question

mass
1000 kg
A truck of
increases its velocity from 60 km/h
to 80 km/h in 10 sec. Calculate the applied force of the truck​

Answer 1

Answer:

Weight of truck = Force = 1000 kgf

Mass = 1000 kg

Initial velocity = 36 km\ h^{-1}km h−1

= \frac{36\times1000}{60\times60}60×6036×1000 = 10 m\ s^{-1}m s−1

New velocity = 72 km\ h^{-1}km h−1

= \frac{72\times1000}{60\times60}60×6072×1000 = 20 m\ s^{-1}m s−1

Work done = Increase in energy

= \frac{1}{2}mv^2-\frac{1}{2}mu^221mv2−21mu2

= \frac{1}{2}m\left(v+u\right)\left(v-u\right)21m(v+u)(v−u)

= \frac{1}{2}\times1000\times30\times1021×1000×30×10

= 150000 J

= 1.5\times10^5\1.5×105  J

Answer 2

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HERE IS UR ANSWER

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the applied force of the truck is 1.5×10^5 J