Question

Mass=3kg,speed=2.0m/s changed in 25 sec at 3.5m/s

Answer 1

Answer:

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

$v=u+at</p><p>a=t(v−u)</p><p></p><p>   =25(3.5−2)=0.06m/s2</p><p></p><p></p><p></p><p>$

As per Newton's second law of motion, force is given as:

$F=ma</p><p></p><p>    =3×0.06=0.18N</p><p></p><p>$

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

Explanation:

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Answer 2

Solution:.

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v=u+at

a=(v−u)÷t

=(3.5−2)÷25

=0.06m/s^2

As per Newton's second law of motion, force is given as:

F=ma

=3×0.06=0.18N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

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