Question

mass 5.5 kg revolve in horizontall circle radius 3 with unifrom speed of 12 ms find omega

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Answer 1

Answer:

change in momentum is 2 mv

Answer 2

Question :

Mass of 5.5 kg revolve in horizontal circle radius 3 with uniform speed of 12 m/s find omega

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Given :

• Mass (m) = 5.5 kg
• Radius (r) = 3 m
• Speed (v) = 12 m/s

To find :

• Angular velocity (ω) = ?

Solution :

Velocity of a body moving in horizontal circle is given by,

⇒ v = r * ω

Putting values we get,

⇒ 12 = 3 * ω

⇒ 12 = 3ω

⇒ ω = 12/3

⇒ ω = 4 rad/s

∴ Angular velocity of body , ω = 4 rad/s     [Required answer]

                                                                                                                 

More informations :

What is centripetal force?

Centripetal force is one kind of force which makes an object to follow a curved path.

Now if we want to find centripetal fore of the given question :

⇒ Centripetal force, Fc = mv²/r

⇒ Fc = (5.5 * 12²)/3

⇒ Fc = (5.5 * 144)/3

⇒ Fc = 5.5 * 48

⇒ Fc = 264 N

∴ Centripetal force acting = 264 N