mass 5kg,force 2N,work done by force in 10s
Answers
Answer:
w=40 J
Explanation:
a=F/m
a=2/5 m/s²
s=1/2at² (because u is zero)
s=1/2*2/5*10²
s=2/10*100
s=20m
W=F.S
w=2*20
w=40 J
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Answer:
The work done by the force in 10 s is 40 J.
Explanation:
The object is moved from rest. So initial velocity, u = 0
Mass of the object, m = 5 Kg
Force on the object, F = 2 N
Acceleration (a) of the object can be found using the equation:
F = ma
a = F/m
a = 2/5
a = 0.4 m/s²
The final velocity of the object can be calculated using the 1st equation of motion.
v = u + at
v = 0 + (0.4 × t)
v = 0.4t
The work done by the force will be equal to the kinetic energy of the object.
∴ K.E = (mv²) / 2
= (5 × (0.4t)²) / 2
= 0.4 t²
So the kinetic energy in 10 seconds will be:
K.E = 0.4 × 10²
K.E = 40 J
This will be the work done on the object.