Mass and energy balance equation for single effect evaporation
Answers
Explanation:
1) A triple-effect evaporator is concentrating a solution that has no appreciable boiling point elevation. The temperature of steam to the first effect is 381.3 K
o o
. . . .The overall heat transfer coefficients in first, second and third-effect are 2800,2200 and 1100 W/m
2
K respectively. At what temperatures will the solution boilin the first and second effects?Solution:Total tem erature dro =
∆
T = 381.3
–
324.7 = 56.6 K
∆
T =
∆
T
1
[1+ (U
1
/U
2
) + (U
1
/U
3
)]56.6 =
∆
T
1
[1+ (2800/2200) + (2800/1100)]
∆
T
1
= 11.75 K
∆
T =
∆
T
2
[1+ (U
2
/U
1
) + (U
2
/U
3
)]56.6 =
∆
T 1+ 2200/2800 + 2200/1100
10
∆
T
2
= 14.95 K
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Answer:
In a single-effect evaporator, steam provides energy for vaporization and the vapor product is condensed and removed from the system. In a double-effect evaporator, the vapor product off the first effect is used to provide energy for a second vaporization unit.