Question

mass in gram of 5.136mol of ag2co3​

Answer 1

Solution :-

Firstly finding mass of 1 mole of $\textbf{\textsf{Ag _2 CO _3 }}$

As we know that ,

Each mole of :-

• Ag = 107.8 u
• C = 12 u
• O = 16 u

Substituting we have ,

$\dashrightarrow\sf 107.8(2) + 12 + 16(3)$

$\dashrightarrow\sf 215.6 + 12 + 48$

$\dashrightarrow$ 275.6 units

Hence ,mass of one mole of

$\textbf{\textsf{Ag _2 CO _3 }}$ is 275.6 units

Now , finding for 5.136 mole .

⇒ 5.136 ( mass of one mole of $\textbf{\textsf{Ag _2 CO _3 }}$ )

⇒ 5.136 ( 275.6 )

⇒ Mass of 5.136 moles of 1107.32 units

Answer 2

Molar masses of:-

• Ag = 108 g
• C = 12 g
• O = 16 g

∴ Molar mass of Ag2CO3 = 2(108 g) + 12 g + 3(16 g)

⇒ Molar mass = 216 g + 12 g + 48 g

⇒ Molar mass = 276 g mol^-1

Now we know,

Mass = (Molar mass)(No. of moles)

⇒ Mass = (5.136 mol)(276 g mol^-1)

⇒ Mass = 1417.5 g (ans.)