mass in grams of 1.05 moles of CuSO4.5H2O
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Answer:-
262.5 g
Explanation:-
• Molar mass of Copper (Cu) = 64 g/mol
• Molar mass of Sulphur (S) = 32 g/mol
• Molar mass of Hydrogen (H) = 1 g/mol
• Molar mass of Oxygen (O) = 1 g/mol
∴ Molar mass of CuSO₄.5H₂O :-
= 64 + 32 + 16×4 + 5(1×2 + 16)
= 96 + 64 + 5(18)
= 160 + 90
= 250 g/mol
Now, we know that :-
Mass = No of moles × Molar mass
=> Mass = 1.05 × 250
=> Mass = 262.5 g
Thus, mass of the sample is 262.5g .
Some Extra Information:-
No of moles :-
(1) Given Mass/Molar mass
(2) No of particles/Avogadro Numver
Molar mass :-
= Mass/No of moles
Number of atoms/molecules :-
= No of moles × Avogadro Number
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