Question

Mass, in grams, of 3 × 1021 molecules of Aspirin, C9H8O4​

Answer 1

Step-by-step explanation:

The number of constituent particles or atoms present in one mole of a substance is known as Avogadro number. It is equal to 6.023 × 1023 mol-¹

The number of moles of a species is given by the expression (1) in which n represents the number of moles, m represents the given mass and M represents the molar mass.

n=m/M ...........(1)

help_outline

fullscreen

Step 2

The number of moles of aspirin (n) is calculated by dividing its number of atoms by Avogadro number.

1st image...(see☝️at top)

The mass of aspirin molecules in the given sample ...

2nd image (see.at.top)

Answer 2

Concept Introduction:-

It may be in the form of a word, a symbol, or a figure that reflects the arithmetic value of a quantity.

Given Information:-

We have been given that$3\times 10^{21}$molecules of Aspirin, $C_9H_8O_4$

To Find:-

We have to find that the mass of Aspirin, $C_9H_8O_4$

Solution:-

According to the problem

The mass$=\left(3 \times 10^{21}\right. molecules ) \times\left(\frac{1 \text { mole }}{6.02 \times 10^{23} \text { molecules }}\right) \times\left(\frac{180 \text { grams }}{1 \text { mole }}\right)=0.89 gram$

Final Answer:-

The mass of $3 \times 10^{21}$ molecules of aspirin $C_9H_8O_4$ is $0.89$ grams.

#SPJ2