Mass M is distributed over a rod of length L. If the linear mass (lambda) linearly increases with length as lambda= kx. The moment of inertia of the rod about one end perpendicular to rod is
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linear mass density of the rod is given by
now we have
integrate both sides
so above is the total mass of rod
now by the formula of center of mass
now plug in value of mass of rod
so above is the position of center of mass of rod
now we have
integrate both sides
so above is the total mass of rod
now by the formula of center of mass
now plug in value of mass of rod
so above is the position of center of mass of rod
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