Question

Mass 'm' shown in figure is in equilibrium. If it is displaced further by 'X'and released, then find its acceleration just after it is released. Takepulleys, springs and strings to be ideal.4kx/5m2kx/5m4kx/m4kx/3m​

Answer 1

Answer:

HOPE IT HELPS.!!!!.

Explanation:

Initially the block is at rest under of force 2T upwards and mg downwards. when the block is pulled downwards by x, the spring extends by 2x.

Initially the block is at rest under of force 2T upwards and mg downwards. when the block is pulled downwards by x, the spring extends by 2x. hence tension T increases by 2kx. thus the net unbalanced force on block of mass m is 4kx.

Initially the block is at rest under of force 2T upwards and mg downwards. when the block is pulled downwards by x, the spring extends by 2x. hence tension T increases by 2kx. thus the net unbalanced force on block of mass m is 4kx. ∴ acceleration of the block is =

Initially the block is at rest under of force 2T upwards and mg downwards. when the block is pulled downwards by x, the spring extends by 2x. hence tension T increases by 2kx. thus the net unbalanced force on block of mass m is 4kx. ∴ acceleration of the block is = m

Initially the block is at rest under of force 2T upwards and mg downwards. when the block is pulled downwards by x, the spring extends by 2x. hence tension T increases by 2kx. thus the net unbalanced force on block of mass m is 4kx. ∴ acceleration of the block is = m4kv

Initially the block is at rest under of force 2T upwards and mg downwards. when the block is pulled downwards by x, the spring extends by 2x. hence tension T increases by 2kx. thus the net unbalanced force on block of mass m is 4kx. ∴ acceleration of the block is = m4kv