Question

Mass number of a radioactive element is
232 and its atomic number is 90. When
this element undergoes certain nuclear
reactions, it transforms into an isotope of
lead with a mass number 208 and an atomic
number 82. Determine the number of alpha
and beta decay that can occur. ​

Answer 1

Answer:

Explanation:α=6,β=4

α=6,β=0

α=4,β=6

Answer :

b

Solution :

Number of α

-paticles emitted =232−2084=6

Decreases in charege number due to α

-emission =12

But actual decrease in charege number =90−82=8

.

Clearly, four β

-particles are emitted.