Mass numbers of two isotopes of an element differ by 2 units (A and A+2). Average atomic mass is 0.5 more than the lower mass number. What could be the ratio of the two isotopes?
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Answer:
Explanation:
From the question it is clear that only two isotopes of the element exist in nature. Let us take their abundances to be x
Final Atomic Mass = (Abundance of 1st * Atomic Mass of 1st Isotopes) + (Abundance of 2nd * Atomic Mass of 2nd Isotopes)
A+0.5=(x∗A)/100+((100−x)∗(A+2))/100
100A+50=Ax+100A+200−Ax−2x
50=200−2x
2x=150
x=75
Hence isotope with atomic mass A has an abundance of 75% and that with (A+2) has 25%.
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Answer:
Explanation:
The ratio of the two isotopes could be 75:25...
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