Mass of 1.2 liter of ozone
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Answer:
The right answer of given answer is 2.54 grams
Explanation:
Moles = given volume / 22.4 = 0.053 moles.
1 Moles of O3= 48grams
0.053 moles of O3 = 0.053* 48 =2.54 grams
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