mass of 1 m3 of water at 4 deg. Celsius
A 1000 kg
B 1000 g
C 100 g
D 100 kg
Answers
Answered by
3
Answer:
L
V
=2.25×10
−6
J/kg
m=1kg
p=1×10
2
pa
volume of water (V)=10
−3
m
3
volume of steam (V)=
0.6
1
m
3
Increase in volume=(
0.6
1
−
1000
1
)=1.7m
3
Work done by system=P(AV)=(1×10
5
)(1.7)
=1.7×10
5
j
△Q=ml
v
=2.25×10
6
j
change in internal energy △U=△Q−△W
△U=2.25×10
6
−1.7×10
5
△U=2.25×10
6
−0.17×10
6
△U=2.08×10
6
j
Answered by
0
Answer:
Hi mate ur answer is option b
1000 g
Hope this answer may help you mate so mark me as Brainlist........
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